Saturday, December 31, 2005

The Answer

To the most difficult equation in the world to balance. This might just work:

88 H2 + 15 Ca(CN)2 + 6 NaAlF4 + 10 FeSO4 + 3 MgSiO3 + 6 KI + 2 H3PO4 + 6 PbCrO4 + 12 BrCl + 3 CF2Cl2 + 20 SO2 -> 6 PbBr2 + 6 CrCl3 + 3 MgCO3 + 6 KAl(OH)4 + 10 Fe(SCN)3 + 2 PI3 + 3 Na2SiO3 + 15 CaF2 + 79 H2O

Look at all of that water :-)

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